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2=5x^2+9x+6
We move all terms to the left:
2-(5x^2+9x+6)=0
We get rid of parentheses
-5x^2-9x-6+2=0
We add all the numbers together, and all the variables
-5x^2-9x-4=0
a = -5; b = -9; c = -4;
Δ = b2-4ac
Δ = -92-4·(-5)·(-4)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-1}{2*-5}=\frac{8}{-10} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+1}{2*-5}=\frac{10}{-10} =-1 $
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